Originally Posted by twig
Schrodinger, your math isn't quite right. I would agree that that adding a partner more than doubles your issues. By your formula moving from single to just one partner would only double the number of issues. You should make n=2 a special case and apply 2^n-1 to n>2.
I wonder what happens when you add imaginary partners. Are they represented by i/ You would start having trigonometric issues.
If you haven't guessed I'm a math geek.
I know you already retracted your statement, but just to clear it up for everyone else... 2^2 - 1 = 4 - 1 = 3 --> 3x the issues of 1 person.
Even for n = 0, a non-existant person has 2^0 - 1 = 1 - 1 = 0 issues......... but that depends on whether you're a nihilist or not!
As for imaginary partners... Then things get complex!!!!!!!!!!